What is the x-intercept of the graph of the function f(x) = x2 − 16x + 64?
(−8, 0)
(0, 8)
(8, 0)
(0, −8)

Answer is (8, 0)


x-intercept y = 0

(x-8)(x-8) = 0
so x - 8 = 0 so x =8

It's (8,0).

If you graph this function you can see that the parabola has an x-intercept at (8,0). This also happens to be the vertex and minimum as well.

X= 49; x = 4step 1: foilstep 2: equal both to 0step 3: find x individually