The temperature, t, in burrtown starts at 21°f at midnight, when h = 0. for the next few hours, the temperature drops 4 degrees every hour. which equation represents the temperature, t, at hour h?
a. t = 21h + 4

b. t = 4h + 21

c. t = –4h + 21

d. t = –21h + 4

C. t = –4h + 21

Step-by-step explanation:

We know that when h = 0, t = 21°F. Replacing h = 0 in  equation A and D we get:

A.

t = 21h + 4

t = 21(0) + 4

t = 4

D.

t = –21h + 4

t = –21(0) + 4

t = 4

So, none of them are correct.

The temperature drops 4 degrees every hour, this means that for h = 1 then t = 21 - 4 = 17. Replacing h = 1 in  equation B and C we get:

B.

t = 4h + 21

t = 4(1) + 21

t = 25

C.

t = –4h + 21

t = –4(1) + 21

t = 17

In consequence, C is the correct option.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

goog may have it for you