Find the possible value or values of z in the quadratic equation z2 – 4z + 4 = 0. a. z = 2√ 2 + 2, z = −√ 2 + 2 b. z = 2 c. z =√ 2 + 2, z = −√ 2 + 2 d. z = 10, z = 6

Start with the given equation
Let's use the quadratic formula to solve for z
Start with the quadratic formula
Break up the expression.
Combine like terms
Simplify
So the solution is z=2 (with a multiplicity of 2) z^2 - 4z + 4 = 0
Factor to get:
(z-2)(z-2) = 0
Since the product is zero, one of the factors must be zero:
z-2 = 0
Therefore z = 2

2/1 or just 2. sorry if i get this wrong