The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 24.5 m/s is
h = 2 + 24.5t − 4.9t2
after t seconds. (round your answers to two decimal places.)

The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 24.5 m/s is h = 3 + 24.5t − 4.9t2 after t seconds. 

With what velocity does it hit the ground? 
Vf = √Voy^2+2gh = √24.5^2+6*9.8 = 25.67 m/sec
I hope my answer helped you, though you didn't indicate what your question was. I assumed that you are looking for the velocity when it hits the ground.

Uneed to add them up 27+18+23=68