What is the variation constant for an inverse squared relationship where we know x = –4 and y = 3?

a. 48
b. –48
c. 16
d. –16

Let the constant be k.

For an inverse squared proportion the formula is y = k/x^2

Insert values of y and x into the formula.
3 = k/(-4)^2
3(-4)^2 = k
k = 3(16)
k = 48

Hope this helps. :)

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