If f(x)=integral of sqrt(t^3+1) dt from 0 to x, then f'(2)=?

F'(2) = 3

Using Fundamental Theorem of Calculus:

Since x = 2, you now have:

so F'(x) =

--> F'(2) = = = 3

so F'(2) = 3

i don't even know man. edge inuity be messing with us. i had to ask a question too.

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it