What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0) ?

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y- = (x-2)

(2,5)(3,0)
slope = (0 - 5) / (3 - 2) = -5/1 or just -5

y = mx + b
slope(m) = -5
use either of ur points...(2,5)...x = 2 and y = 5
now we sub and find b, the y int
5 = -5(2) + b
5 = -10 + b
5 + 10 = b
15 = b

so ur equation is : y = -5x + 15

or if u need it in point slope form
y - y1 = m(x - x1)
slope(m) = -5
(2,5)...x1 = 2 and y1 = 5
now we sub
y - 5 = -5(x - 2)

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