Ido not understand how to do !
#2,3,6,7

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

15 and 14.7 are 1 apart, so 15 – 14.7 must be 1.

y=2x−1 5x−4y=1 is (1,1)(1,1) a solution of the system?