Find the critical point of the function f(x) = x^2 - 2x + 7.
a: (-1, 10)
b: (-1, 6)
c: (1,0)
d: (1, 6)

The critical points are where the slope is 0
take the derivitive
f'(x)=2x-2

find where it equals 0
0=2x-2
2=2x
1=x
at x=1
sub that back into original function to find the y value of the critical point
f(1)=1^2-2(1)+7
f(1)=1-2+7
f(1)=-1+7
f(1)=6

the point is (1,6)
D is answer