One zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

x=-2, x=1, x=3

Step-by-step explanation:

Step-by-step explanation:

one zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

the following polynomials have the function  

f(x)=x^3-2x^2-5x+6

note 2 is not a zero of the function

but x=-2

to find the other zeros we say  

f(x)/x+2=x^3-2x^2-5x+6/(x+2)

we have the quadratic equation  

x^2-4x+3

factorizing the above, using factorization method

(x^2-3x-x+3)

(x^2-3x)(-x+3)

x(x-3)-1(x-3)

(x-1)(x-3)

x=1, x=3

the zeros of the function are  

x=-2, x=1,x=3

substituting the values back into the function

we have zero

f(1)=1^3-2(1)^2-5(1)+6

F(1)=0

anser is a

step-by-step explanation:

negitive slope

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches