Help me pls?

A

Step-by-step explanation:

Given

y = - x² + 6x - 1

Since the coefficient of the x² term < 0 , then graph is a maximum

The only 2 possible are A and D

Calculate the coordinates of the vertex

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

= -

y = - x² + 6x - 1 ← is in standard form

with a = - 1 and b = 6 , then

= - = 3

Substitute x = 3 into the equation for y- coordinate of vertex

y = - 3² + 6(3) - 1 = - 9 + 18 - 1 = 8

vertex = (3, 8 )

Graph A has its vertex at (3, 8 )

Then graph A best represents y = - x² + 6x - 1

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.