HELP HELP !! & PlEASE SHOW WORK ! What would be the compound interest rate if Tom borrowed $6,000 at a 3% interest rate for 2 years? $365.40
$185.40
$180.00
$250.00

Compound interest = $365.4

Step-by-step explanation:

Given:

Amount borrowed = $6,000

Rate of interest = 3%

Number of year =  year

Find:

Compound interest

Computation:

A = P[1+r]ⁿ

Amount after 2 year = 6,000[1 + 3%]²

Amount after 2 year = 6,000[1 + 0.03]²

Amount after 2 year = 6,000[1.03]²

Amount after 2 year = 6,000[1.0609]

Amount after 2 year = 6,365.4

Compound interest = Amount after 2 year - Amount borrowed

Compound interest = 6,365.4 - 6,000

Compound interest = $365.4

d

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hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2