An independent-samples t test was conducted to compare high-altitude exercise to exercise at sea-level. Imagine the mean comfort level of participants, rated on a 7-point scale where high values reflect high comfort, at high altitude was 3.5 while the average at sea-level was 5.1. Imagine also that values were calculated for sdifference of 1.1, 2.04 for pooled variance, and 35 for degrees of freedom total. What are the critical cutoffs for this test

Find the roots of the equation below. x^2 - 6 + 9 = 0

I've been working on this for a few days and i just don't understand, it's due in a few hours. you.the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α.part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part bsuppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case.part cnow try a numerical problem. what is the direction of the vector w = < -1, 6 > ?

Write as a product of two polynomials. 2(3–b)+5(b–3)^2