The amount of flight time between failures of an airplane engine is exponentially distributed with mean 900 hours. If the engine is inspected every 600 hours of flight time, what is the probability that the engine will fail before it is inspected

0.4866 = 48.66% probability that the engine will fail before it is inspected

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

In which is the decay parameter.

The probability that x is lower or equal to a is given by:

Which has the following solution:

The probability of finding a value higher than x is:

Exponentially distributed with mean 900 hours.

This means that

If the engine is inspected every 600 hours of flight time, what is the probability that the engine will fail before it is inspected?

This is , which is:

0.4866 = 48.66% probability that the engine will fail before it is inspected

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.