If a basketball is bounced from a height of 15 feet, the function f(x)=15(.75)^x gives the height of the ball in feet of each bounce, where x is the bounce number. What will be the height of the 5th bounce? Round to the nearest tenth of a foot.

3.5595feet

Step-by-step explanation:

Given the function f(x)=15(.75)^x which models the height of the ball in feet of each bounce, where x is the bounce number. The height after the 5th bounce will be gotten by substituting x = 5 into the function

f(x)=15(.75)^x

f(5)=15(.75)^5

f(5)=15(0.2373)

f(5)= 3.5595

Hence the height after the 5th bounce is 3.5595feet

the answer is 3.6 if you’re rounding to the nearest 10th of a foot

Step-by-step explanation:

.75 to the power of 5 times 15

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!