Mathematics, 18.04.2021 01:20 frankcaroccio0203

An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2 at^2 + v0t + s0 for the object. At t = 1 second, s = 136 feet
At t = 2 seconds, s = 104 feet
At t = 3 seconds, s = 40 feet

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An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2 at^2 + v0t + s0 for the object. At t = 1 second, s = 136 feet At t = 2 seconds, s = 104 feet At t = 3 seconds, s = 40 feet

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Another question on Mathematics

An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2 at^2 + v0t + s0 for the object. At t = 1 second, s = 136 feet
At t = 2 seconds, s = 104 feet
At t = 3 seconds, s = 40 feet