Can Somone Help me with my homework ​

part A) yes, the bases and heights are the same

Part B) yes, the bases and heights are the same

Part C) not enough info

Step-by-step explanation:

Part C)

area of the circle = π(1/2h)²

area of ellipse = π(1/2h)(1/2 major axis)

Part A:

The area of a triangle is given by the product of its base and the height relative to that base.

Since theses triangles have the same base b and same height h, they have the same area.

Part B:

The area of a rectangle or parallelogram is given by the product of base and height. Since these figures have the same base and height, they have the same area.

Part C:

These figures have different shapes, so we can't affirm that they have the same area.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)