Write a quadratic function in the given form whose graph satisfies the given condition. has a vertex of (5, -2) & passes through the point (3, 6) in vertex form

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f(x) = 2(x-5)²-2

Step-by-step explanation:

The equation of a parabola in vertex form is y=a(x-h)²+k where (h,k) is the vertex and "a" represents how stretched or compressed the parabola is and what direction it travels.

Given a vertex of (5,-2) the equation so far is y=a(x-5)²-2

Since we want the parabola to pass through the point (3,6) we must find a value of "a" that satisfies this:

y=a(x-5)²-2

6=a(3-5)²-2

6=a(-2)²-2

6=4a-2

8=4a

2=a

This means that the quadratic function is f(x) = 2(x-5)²-2

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: