An object is launched vertically at a velocity of 160 feet per second from the top of a building 100 feet above the ground. Use the model h=-16t^2+vt+c where h is the height of the object at any time t, c is the initial height, in feet, of the object, t is the time in seconds and v is the velocity of the object.
How long will it take the object to reach the maximum height, and what is the maximum height?(Round to the nearest whole number)

The question let's us set up the equation

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Step-by-step explanation:

160= 16t^2+96t+16 and we just solve for t to get t= 3(sqrt 2 - 1) and -3(sqrt 2 - 1).

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f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get