Find the 75th term of the following arithmetic sequence.
6, 11, 16, 21,

The 75th term in the sequence is 16

Step-by-step explanation:

The 75th term of a sequence can be considered as the term that is in the position at 75% along the sequence. This is assuming that the sequence has been sorted already from lowest value to highest value

In this sequence, which has 4 terms, we can find the 75th term by finding what term is at 75% (or three-quarters) along the sequence.

To find the 75th term:

Multiply the number of terms by 0.75 (or 75%/100%) :

             0.75*4 terms= 3

Then, we find the value of the term that is at position 3 from the left (lowest number)

In this case, the term that is at the 3rd position from the left is 16

Thus, the 75th term in the sequence is 16

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°