Geoff wants to make a 200 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with a 8% alcohol solution. What are the quantities of each of the two solutions (3% and 8%) he has to use?

Volume of 3% alcohol = 80 ml

Volume of 8% alcohol = 120 ml

Step-by-step explanation:

Final volume of 6% alcohol solution = 200 ml

Let the volume of 3% alcohol volume = a ml

Therefore, volume of 8% alcohol = (200 - a) ml

Equation for the given situation will be,

3a + 8(200 - a) = 6×200

3a + 1600 - 8a = 1200

1600 - 5a = 1200

5a = 400

a = 80 ml

Therefore, volume of 3% alcohol to be used = 80 ml

And volume of 8% alcohol to be used = (200 - 80) = 120 ml

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: