An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t^2 + 19.6t + 58.8, where s is in meters. How high will the object be after 2 seconds?

78.4 feet
117.6 feet
194. 04 feet
1.96 feet

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

c: lkllmn.

hope it's you

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?