Mathematics, 16.04.2021 20:40 heavyhearttim
Find the horizontal asymptote of y=x+3/x^2-4x+3β
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Simplify. β4x^2 (5x^4β3x^2+xβ2) β20x^6β12x^4+8x^3β8x^2 β20x^6+12x^4β4x^3+8x^2 β20x^8+12x^4β4x^2+8x β20x^6+12x^4+4x^3β8x^2
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Find the horizontal asymptote of y=x+3/x^2-4x+3β...
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