In a game of luck, a turn consists of a player rolling 121212 fair 666-sided dice. Let X=X=X, equals the number of dice that land showing "111" in a turn. Find the mean and standard deviation of XXX. You may round your answers to the nearest tenth.

The mean of X is 2 and the standard deviation is 1.3.

Step-by-step explanation:

For each dice rolled, there are only two possible outcomes. Either it lands on one, or it does not. The probability of a dice rolled landing on one is independent of any other dice. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

The standard deviation of the binomial distribution is:

Probability of rolling a 1.

Six sides, so:

12 dices are rolled:

This means that

Find the mean and standard deviation of X

The mean of X is 2 and the standard deviation is 1.3.

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno