The terminal side of an angle theta, intercepts a circle at quadrant II whose center is located at the origin and has a radius of 82. the y-coordinate of the point of interception is 18. Find the value cos theta. 1)-9/40
2)-9/41
3)-40/41
4)-40/9

The answer is the

4)-40/9

Can I please get brainliest

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: