What is the probability of rolling a 3 on a 6-sided 8) number cube and then NOT rolling a 3 on a 6-
sided number cube?

the chances of rolling a 3 are 1/6

the changes of not doing it is 5/6

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b