What is the perimeter of the rectangle whose vertices are at (6, 3), (−6, 3), (−6, −1), and (6, −1)?

Given:

The vertices of a rectangle are (6, 3), (−6, 3), (−6, −1), and (6, −1).

To find:

The perimeter of the rectangle.

Solution:

Distance formula:

Let the vertices of a rectangle are A(6, 3), B(−6, 3), C(−6, −1), and D(6, −1).

Using the distance formula, we get

Similarly,

Now, the perimeter of the rectangle is:

Therefore, the perimeter of the rectangle is 32 units.

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: