Can any on help on 4-6 only please it would be grateful

4. h=9in

5. 150.8

6. 301.6

Step-by-step explanation:

4.

Surface area of a rectangular prism form : A=2(wl+hl+hw)

Substitute in values from the question: 558=2[(9)(11)+h(11)+h(9)]

Multiply where applicable: 558=2[(99)+11h+9h]

Combine like terms: 558=2[(99)+20h]

Divide both sides by 2: 279=(99)+20h

*note- This step can also be seen as multiplying the right side by 2 without messing with the left at all (558=(198)+40h) then you would solve in the same fashion as I will from here just with the alternative numbering*

Subtract to isolate the h: 180=20h

Divide both sides to isolate the h: 9=h

Now we see that the missing dimension h=9in

*note- I did not bold the equations with squares so please don't be confused by that*

5.

Surface area of a cylinder form: A=2πrh+2π

Substitute in values from the question: A=2π(3)(5)+2π

Multiply were applicable: A≈94.2+56.5

Add remaining values: A≈150.8

Now we see that the total surface area is 150.8

*note- whenever we solve for volume or SA of a figure we square the unit (➞)*

6.

Surface area of a cylinder form: A=2πrh+2π

Substitute in values from the question: A=2π(6)(2)+2π

*note- we use 6 instead of the given value 12 because the equation calls for the radius and not the diameter*

Multiply were applicable: A≈75.2+226.2

Add remaining values: A≈301.6

Now we see that the total surface area is 301.6

*note- whenever we solve for volume or SA of a figure we square the unit (➞)*

Hope this helps :)