The Math and Verbal SAT scores for a random sample of 10 students from a large introductory statistics course are provided. Student 1 2 3 4 5 6 7 8 9 10 s Math SAT 640 620 700 680 600 720 770 580 660 580 655 63.1 Verbal SAT 580 690 560 560 600 700 620 620 710 500 614 68.8 Differences (Math - Verbal) 60 -70 140 120 0 20 150 -40 -50 80 41 81.0 Which data analysis method is more appropriate in this situation: paired data difference in means or difference in means with two separate groups

Step-by-step explanation:

answer: the common difference is -0.10

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: