Jeff drew a circle inside a square, as shown below. Which method can Jeff use to find the area of the
square not covered by the circle?

3.14

Step-by-step explanation:

Ok, I didn't find the graph but jeff can use the radius of the circle as the diamation of the square

If the radius is (r) so the area is

A = r * r

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

the solution is 12x-6y