Solve for b 2 in A = h(b 1+b 2), if A = 16, h = 4, and b 1 = 3. b 2 =

b2 = 1

Step-by-step explanation:

A = h(b1 + b2)

Given:

A = 16

h = 4

b1 = 3

b2 = x

Work:

A = h(b1 + b2)

16 = 4(3 + x)

16 = 12 + 4x

4x = 16 - 12

4x = 4

x = 1

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: