Mathematics, 15.04.2021 14:00 ale3133

Find the total surface area of this cone. Leave your answer in terms of T.
24.in
SA =? - in2

Find the total surface area of this cone.

Leave your answer in terms of T.
24.in
SA =? - in2

Answers: 2

Show answers

Answers

Answer from: icemaniac

SA = 360π in²

Step-by-step explanation:

The slant height l is the hypotenuse of the right triangle inside the cone.

Using Pythagoras' identity to find l

l² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

l = $\sqrt{676}$ = 26

Then

SA = πrl + πr²

= (π × 10 × 26) + (π × 10²)

= 260π + 100π

= 360π in²

Answer from: russboys3

SA = 360π in²Step-by-step explanation:

The slant height l is the hypotenuse of the right triangle inside the cone.

Using Pythagoras' identity to find l

l² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

$l = \sqrt{676}$

676

= 26

Then

SA = πrl + πr²

= (π × 10 × 26) + (π × 10²)

= 260π + 100π

= 360π in²

Answer from: Quest

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

Answer from: Quest

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

$ab^2+ac^2=bc^2$

$ab^2+ac^2=x^2$ )

triangle abd and cba are similar,

$\frac{ab}{bc}=\frac{bd}{ab}$

$ab^2=bc\cdot bd$

$25=bc\cdot bd$ (2)

triangle cad and cba are similar,

$\frac{ac}{bc}=\frac{cd}{ac}$

$ac^2=bc\cdot dc$

$7\times 7=bc\cdot dc$

$49=bc\cdot dc$ )

using (1), (2) and (3), we get

$25+49=x^2$

$74=x^2$

hence proved.

therefore option 2 is correct.

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