Mathematics, 14.04.2021 22:20 sunny644
when x = 3/4, q(3/4) = 6(3/4)^3 + 19(3/4)^2 – 15(3/4) – 28 = -26, therefore, 3/4 is not a root for the function q(x) = 6x^3 + 19x^2 – 15x – 28.
Answers: 1
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when x = 3/4, q(3/4) = 6(3/4)^3 + 19(3/4)^2 – 15(3/4) – 28 = -26, therefore, 3/4 is not a root for t...
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