The height (ft) of an object is launched into the air given by the function h(t)=-6t^2+120t+17 where t is the time in seconds. When will the obj reach its maximum height ?
What is the max height?
After how many seconds will it hit the ground?

Object will reach the max height in 10 seconds.

Max. height is 1817.

It will hit the ground in 20 seconds.

Step-by-step explanation:

In order to find the x value which makes the function take its greatest value, you need to take the derivative of the function and equalize the result to 0.

h'(t)=-12t+120=0

t=10

The object will reach its maximum height in 10 seconds.

h(10) (maximum height) = 6.10.10+120.10+17= 600+1200+17=1817

Considering this is a parabola, time in total is two times more than the time passed until reaching the max. height.

10.2=20

is there answer choices?

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet