Abuilding lot in a city is shaped as a 30 degrees, -60 degrees, -90 degrees triangle. the side opposite the 30 degrees angle measures 41 feet.

a. find the length of the side of the lot opposite the 60 degrees angle.

b. find the length of the hypotenuse of the triangular lot.

c. find the sine, cosine, and tangent of the 30 degrees angle in the lot. write your answers as decimals rounded to four decimal places.

If you want to solve this problem on your own, you could just view my answers:

a. 41 square root of 3

b. hypotenuse= 41x2= 82 ft.
 
c. sine: 41/82-.5

cos: 41sqr. rt. 3/82= .8660

tan: 41/ 41 square root 3= .5774

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One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to