The probability that a blue eyed person is left handed is 1/7. the probability that left handed person is blue eyed is 1/3. the probability that a person has neither of these attributes is 4/5. what is the probability that a person has both these attributes?

P (L given B)= 1/7 
so (# L + #B)/#B = 1/7, so #B = 7, so # not L and B = 6 
P(B given L)= 1/3 
so (#B +#L)/#L = 1/3, so #L= 3, so # not L=2 
total combinations of L and B = #L x #B = 3 x 7 = 21 
so # not B = 21-7=14 
so # not L = 21-3=18 
so # not L and not B = 18-6=12 
so P(not B and not L) =12/21 = 2/3

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