Prove:

(2(tan x - cot x) / (tan^2 x - cot^2 x} = sin (2x)

So here is how we are going to prove that (2(tan x - cot x) / (tan^2 x - cot^2 x} = sin (2x). Follow it step by step:
LS  =   2(tanx−cotx)
       
           tan^2−cot^2x
     = 2(tanx−cotx)
   
    (tanx−cotx)(tanx+cotx)
    =        2
     
        (tanx+cotx)
   =        2
     
       Sin2x+cos2x
                sinxcosx
    =      2
     
            1
     
      sinxcosx
   = 2sinxcosx
   = sin2x
I hope that is the answer that you are looking for. Let me know if you need more help next time. Thanks for posting your question here in !

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67