Can someone please help me with this math problem? Please. Simplify the expression:(2x-3y)^2/(3y-2x)^2 Ava simplified the expression and said that the value is -1. (2x-3y)^2/(3y-2x)^2 (2x-3y)^2/-(2x-3y)^2 and then she has both of them crossed out (2x-3y)^2/-1(2x=3y)^2 =-1 Is Ava's solution correct? If not, find and explain her mistake. Give the correct solution.

Ava is incorrect

Step-by-step explanation:

Given

Required

Determine if Ava is correct or not

Ava's solution is incorrect and the proof is as follows;

Apply the following law of indices;

Rewrite the numerator

Cross out the common factor of the numerator and denominator

Hence, the solution is 1; not -1

Her mistake is that, she did not apply the square on -1, after she factorize the denominator

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.