The proof that ΔABC ≅ ΔCDA is shown. Given: ∥ Line segment A B is parallel to line segment C D and Line segment B C is parallel to line segment D A ∥ Prove: ΔABC ≅ ΔCDA Parallelogram A B C D is shown. A line is drawn from point A to point C to form 2 triangles. What is the missing reason in the proof? Statements Reasons 1. AB ∥ CD; BC ∥ DA 1. Given 2. Quadrilateral ABCD is a ▱ 2. Definition of parallelogram 3. AB ≅ CD; BC ≅ DA 3. Opposite sides of a parallelogram are ≅ 4. AC ≅ AC 4. Reflexive property 5. ΔABC ≅ ΔCDA 5. ? perpendicular bisector theorem Pythagorean theorem HL theorem SSS congruence theorem

step-by-step explanation:

what is the figure? attach a picture.

d. all of the above

step-by-step explanation:

the area of a triangle is determined by the formula: base x height * 1/2

you'll need to assign a base to the triangle. based on the vertices given, the simplest base would be the line segment from (-2,1) to (2,1). the distance between any two numbers is found by just subtracting them. here, you should subtract the x values to find the distance of this side.

2 - (-2) = 4.

so the distance (aka the length of the base) is 4. the height of the triangle is the distance between the base and the highest point on the triangle which is (3,4). we should subtract the y values this time to find the height/distance.

4 - 1 = 3

so the height is 3.

base = 4

height = 3

hope this if needed hmu