Please help out and explain the best you can! Tysm !

Step-by-step explanation:

From the graph attached,

Coordinates of the vertices of ΔOAB,

O → (0, 0)

A → (2, 4)

B → (5, 0)

If a point (h, k) is rotated 90° counterclockwise about the origin the image point will be,

(h, k) → (-k, h)

By this rule, if triangle OAB is rotated 90° counter clockwise, new vertices will follow the same rule,

O(0, 0) → O'(0, 0)

A(2, 4) → A'(-4, 2)

B(5, 0) → B'(0, 5)

By plotting these points we can get the image triangle.

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.