Write an exponential function =for a graph that passes through (2,1) and (3,10). Ill give you whatever please help

Step-by-step explanation:

Use coordinates (2,1) and 3,10

The exponential equation is

Plug in the x and y values.xfor both functions of coordinates.

Divide the equation with the larger exponet by the other equation.

Substitute that in for one of the equations.

Solve for a.

So our exponetial equation is

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this