A camera company packs each camera in a cube­shaped box with side lengths of 1/2 ft. Then the company ships the cameras in a container with dimensions of 5 1/2 ft by 7 1/2 ft by 4 1/2 ft. What is the maximum number of camera boxes that will fit in the container?

1,485 camera boxes

Step-by-step explanation:

1/2 ft is 6 inches. So, the cube-shaped camera box has side lengths of 6 inches. Meaning, the volume of the camera box is (6 * 6 * 6) inches^3, or 216 inches^3. Same principle for finding the volume of the container. 5 1/2 ft = 66 inches, 7 1/2 ft = 90 inches, and 4 1/2 ft = 54 inches. So, the volume of the container is (66 * 90 * 54) inches^3, or 320,760 inches^3. Since we are trying to find out how many camera boxes can fit in the container, we divide the volume of the container by the volume of one camera box. The problem looks like this: 320,760 / 216. The quotient, 1,485, is how many camera boxes that can fit inside the container, and is thus our final answer.

brainliest? please. I'll even say a joke if i have to

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .