![\displaystyle x=4\sqrt[3]{y}\\\\\frac{x}{4}=\sqrt[3]{y}\\\\\left(\dfrac{x}{4}\right)^3=y\qquad\text{cube both sides}\\\\\boxed{y=\dfrac{x^3}{64}}](/tpl/images/1256/9281/cbabe.png)
Part 2. Algebraically find the inverse of the function
1. f(x) = -3(x - 4)^2 - 6
2. y =...
Mathematics, 14.04.2021 01:00 kingindoraptor
Part 2. Algebraically find the inverse of the function
1. f(x) = -3(x - 4)^2 - 6
2. y = sqrt (x - 4)^2 + 3
3. y = 4 cube root (x)
Answers: 3
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