"in the 45°-45°-90° triangle above, r = 10. find the other two lengths.
a) p = 3√2, q = 10√2
b) p = 5√2, q = 2√2
c) p = 5, q = 8
d) p = 6√3, q = 8√6
(will draw picture below)"

We are given a right triangle that has angles of 45°-45°-90°. This would indicate that the triangle is an isosceles type. We can use some trigonemetric functions to solve for the other legs. We do as follows:

sin 45 = p / 10

p = 5√2

cos 45 = q /10

q = 5√2

Hope this answers the question. Have a nice day.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47