Mathematics, 13.04.2021 18:20 ilawil6545

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1. - f(x) = − 1/2 (x − 6)^2 + 3/2
- f(x) = 1/2 (x − 6)^2 + 3/2
- f(x) = − 1/2 (x + 3/2)^2 + 6
- f(x) = 1/2 (x + 3/2 )^2 + 6

{{TWENTY EIGHT POINT REWARD. IM SERIOUS. I NEED TO CATCHUP BIGTIME. Much love <3}}

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Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1. - f(x) = − 1/2...

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Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1. - f(x) = − 1/2 (x − 6)^2 + 3/2 - f(x) = 1/2 (x − 6)^2 + 3/2 - f(x) = − 1/2 (x + 3/2)^2 + 6 - f(x) = 1/2 (x + 3/2 )^2 + 6 {{TWENTY EIGHT POINT REWARD. IM SERIOUS. I NEED TO CATCHUP BIGTIME. Much love <3}}

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Another question on Mathematics

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1. - f(x) = − 1/2 (x − 6)^2 + 3/2
- f(x) = 1/2 (x − 6)^2 + 3/2
- f(x) = − 1/2 (x + 3/2)^2 + 6
- f(x) = 1/2 (x + 3/2 )^2 + 6

{{TWENTY EIGHT POINT REWARD. IM SERIOUS. I NEED TO CATCHUP BIGTIME. Much love <3}}