Mathematics, 13.04.2021 17:40 avision42

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x- 12). what is standard form of the equation for this line?

a. x-4y=8
b. x-4y=2
c. 4x-y=8

Answers: 2

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More questions: Mathematics Another questions

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x- 12). what is standard form of the equation for this line? a. x-4y=8 b. x-4y=2 c. 4x-y=8

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Another question on Mathematics

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x- 12). what is standard form of the equation for this line?

a. x-4y=8
b. x-4y=2
c. 4x-y=8