HELP plesse with 9 and 10

Find the solutions below

Step-by-step explanation:

Given the equation

y = -x^2 + 2x + 7

y = -2x+2

Equating both expressions

-x^2 + 2x + 7 = -2x + 2

-x^2 + 2x + 7 + 2x - 2 = 0

-x^2 + 4x + 5 = 0

Multiply through by -1

x^2 - 4x - 5 = 0

Factorize

x^2 - 5x + x - 5 = 0

x(x-5)+1(x-5) = 0

(x+1)(x-5) = 0

x+1 = 0 and x - 5 = 0

x = -1 and 5

when x = -1

y = -2x+2

y = -2(-1)+2

y = 2+2

y = 4

when x = 5

y = -2(5)+2

y = -10+2

y = -8

Hence the solutions are (-1, 4) and (5, -8)

b) y = x^2-3x-27

y = x - 6

Equating both expressions

x^2-3x-27 = x - 6

x^2-3x-27 - x + 6 = 0

x^2-4x-21 = 0

x^2 - 7x + 3x - 21 = 0

x(x-7)+3(x-7) = 0

(x+3)(x-7) = 0

x = -3 and 7

when x = -3

y = -3-6

y = -9

when x = 7

y = 7 - 6

y = 1

Hence the required solutions are (-3, -9) and (7, 1)

(c, 0) i might be wrong so don't put full faith on my answer

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743