Two miners are trying to push a stationary mine cart filled with gold. Miner A is exerting 25 N while miner B is exerting 20 N. However it is observed that the mine cart remained stationary despite their push. How much force does the road exert on the wheel of the cart? a. 25 N

b. 45 N

c. Less than

45 N d. More than 25 N​

b. 45 N

Step-by-step explanation:

The sum of the forces exerted by the two miners = 25 + 20

                                           = 45 N

Since after applying a force of 45 N by the two miners the cart remained stationary, it implies that a resistance force of at least 45 N acts against their push. Thus, the force exerted by the road could be equal to 45 N or greater than 45 N.

Probably, if the sum of the forces applied is 46 N, the cart would move. Which depends on the value of resistance force applied by the road. Thus, the appropriate answer from the given option is B.

Since the force applied on the cart equals the resistance force exerted by the road, the cart would not move.

sorry not sure

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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