Suppose that 5% of the time Todd attends a concert twice a month, 40% of the time he attends a concert once a month, and 55% of the time he doesn't attend a concert at all in a given month. What is the expected value for the number of times Todd attends a concert during a month?

The expected value for the number of times Todd attends a concert during a month is 0.5.

Step-by-step explanation:

We have these following probabilities:

5% probability of attending a concert twice a month, which means that P(X = 2) = 0.05

40% probability of attending a concert once a month, which means that P(X = 1) = 0.4

55% probability of not attending a concert during the month, which means that P(X = 0) = 0.55

What is the expected value for the number of times Todd attends a concert during a month?

We multiply each value by its probability. So

The expected value for the number of times Todd attends a concert during a month is 0.5.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3