Suppose the family wise error rate is 0.05, if there are ten levels of one factor but only 5 comparisons are of importance, what would the individual error rate need to be for each of those 5 comparisons? Group of answer choices 5 0.01 .05 0.10

Individual error rate = 0.01

Therefore, Option b) 0.01 is the correct answer

Step-by-step explanation:

Given the data in the question;

family wise error rate ∝ = 0.05

there are ten levels of one factor but

important comparisons m = 5

the individual error rate need to be for each of those 5 comparisons = ?

we know that;

individual error rate = family wise error rate ∝ / important comparisons m

so we substitute

individual error rate = 0.05 / 5

individual error rate = 0.01

Therefore, Option b) 0.01 is the correct answer

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x

ummm seems that u didnt post the attachement !